Sort Array By Parity LeetCode Solution - The Coding Shala

Home >> LeetCode >> Sort Array By Parity

 In this post, we will learn how to solve LeetCode's Sort Array By Parity Problem and will implement its solution in Java.

Sort Array By Parity Problem

Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A.

Example 1:
Input: [3,1,2,4]
Output: [2,4,3,1]
The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.

Practice this problem on LeetCode(Click Here).

Sort Array By Parity Java Solution

Approach 1

Java Program: 

class Solution {
    public int[] sortArrayByParity(int[] A) {
        int i = 0, j=A.length-1;
        while(i<j){
            if(A[i]%2==1){
                int tmp = A[i];
                A[i] = A[j];
                A[j] = tmp;
            }
            if(A[i]%2==0) i++;
            if(A[j]%2==1) j--;
        }
        return A;
    }
}


Other Posts You May Like
Please leave a comment below if you like this post or found some errors, it will help me to improve my content.
By

Comments

Post a Comment

Popular Posts from this Blog

LeetCode - Crawler Log Folder Solution - The Coding Shala

Home >> LeetCode >> Crawler Log Folder  In this post, we will learn how to solve LeetCode's Crawler Log Folder problem and will implement Crawler Log Folder Java Solution. Crawler Log Folder Problem The Leetcode file system keeps a log each time some user performs a change folder operation. The operations are described below: "../": Move to the parent folder of the current folder. (If you are already in the main folder, remain in the same folder). "./": Remain in the same folder. "x/": Move to the child folder named x (This folder is guaranteed to always exist). You are given a list of strings logs where logs[i] is the operation performed by the user at the ith step. The file system starts in the main folder, then the operations in logs are performed. Return the minimum number of operations needed to go back to the main folder after the change folder operations. Input: logs = ["d1/","d2/","../","d2...
Read more

N-th Tribonacci Number Solution - The Coding Shala

Home >> Programming >> N-th Tribonacci Number  Hey there, welcome back to another post. In this post, we will learn how to solve the N-th Tribonacci Number problem and will implement its solution in Java. N-th Tribonacci Number Problem Statement The Tribonacci sequence Tn is defined as follows: T0 = 0, T1 = 1, T2 = 1, and Tn+3 = Tn + Tn+1 + Tn+2 for n >= 0. Given n, return the value of Tn.  Example 1:  Input: n = 4 Output: 4 Explanation: T_3 = 0 + 1 + 1 = 2 T_4 = 1 + 1 + 2 = 4 N-th Tribonacci Number Java Solution using Bottom-Up DP This problem is similar to the Fibonacci series. We can solve it using the Bottom-Up approach of dynamic programming. Time Complexity: O(n) Space Complexity: O(n) The space complexity can be reduced to O(1) by using variables to store the previous three values instead of using an array. Java Program:  class Solution { public int tribonacci( int n) { if (n == 0) return 0; ...
Read more

Java Program to Convert Binary to Decimal - The Coding Shala

Home >> Java Programs >> Convert Binary to Decimal  Hey there, welcome back to another post. In this post, we will learn how to convert Binary to Decimal in Java. Java Program to Convert Binary to Decimal You have given a binary number, convert it to a decimal number. Example:  Input: 101 Output: 5 Input: 111 Output: 7 Binary to Decimal Conversion in Java Approach We will the below formula to convert binary to decimal: decimal number = (2^0) * (rightmost digit) + (2^1) * (second rightmost digit) + ...  for example:  binary number = 110 decimal number = 2^0 * 0 + 2^1 * 1 + 2^2 * 1 = 1 * 0 + 2 * 1 + 4 * 1 = 0 + 2 + 4 = 6 Java Program:  import java.util.Scanner; /** * https://www.thecodingshala.com/ */ public class Main { public static void printDecimal( int num) { int decimal = 0; int twos = 1; // 2^0 = 1 initial value while (num > 0) { ...
Read more

New Year Chaos Solution - The Coding Shala

Home >> Programming Questions >> New Year Chaos New Year Chaos Problem Solution In this post, you will learn how to solve New Year Chaos Problem and implement its solution in Java. Problem:   It's New Year's Day and everyone's in line for the Wonderland rollercoaster ride! There are a number of people queued up, and each person wears a sticker indicating their initial position in the queue. Initial positions increment from at the front of the line to at the back.  Any person in the queue can bribe the person directly in front of them to swap positions. If two people swap positions, they still wear the same sticker denoting their original places in line. One person can bribe at most two others.  For Example, if n=8 and Person 5 bribes Person 4, the queue will look like this: 1,2,3,5,4,6,7,8. Fascinated by this chaotic queue, you decide you must know the minimum number of bribes that took place to get the queue into its current state. Inpu...
Read more

Java Program to Find LCM of Two Numbers - The Coding Shala

Home >> Java Programs >> Find LCM of Two Numbers  Hey there, welcome back to another post. In this post, we will learn how to find the LCM of two numbers in Java. Java Program to Find LCM of Two Numbers The LCM (Least Common Multiple) is the smallest number that can be divided by both numbers. For example, the LCM of 5 and 10 is 10 because 10 is the smallest number that is divisible by both 5 and 10. Example 1:   Input Number1: 8 Number2: 10 Output LCM of 8 and 10 is: 40 Find LCM of Two Numbers using GCD We can find the LCM of two numbers by using GCD. The relation between LCM and GCD is:  a x b = LCM(a, b) * GCD (a, b) LCM(a, b) = (a x b) / GCD(a, b) For example, LCM(8, 10) is: LCM(8, 10) = ( 8 * 10) / GCD(8,10) LCM(8, 10) = 80 / 2 = 40 Java Program:   import java.util.Scanner; /** * https://www.thecodingshala.com/ */ public class Main { public static int findGCD( int num1, int num2) { if (num1 == 0) {...
Read more