Shell Script to Display the digits which are at odd positions in a given 5-digit number - The Coding Shala

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Shell Script to Display the digits which are at odd positions in a given 5-digit number

Display the digits which are at odd positions in a given 5-digit number.  



Example:

number is 23786

output - 276.

Code: 

#!/bin/bash
echo "enter 5 digit number"
read number
n=1
while((n<=5))
do
a=`echo $number | cut -c $n`
echo -n "$a"
n=`expr $n + 2`
done
echo " "



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