Triplets with Sum between given range - The Coding Shala

Home >> Interview Questions >> Triplets with sum between given range

Triplets with Sum between given range Java Solution

Given an array of real numbers greater than zero in the form of strings.

Find if there exists a triplet (a,b,c) such that 1 < a+b+c < 2 . 

Return 1 for true or 0 for false.
Triplets with Sum between given range - The Coding Shala

Example:
Given [0.6, 0.7, 0.8, 1.2, 0.4] ,
You should return 1
as
0.6+0.7+0.4=1.7
1<1.7<2
Hence, the output is 1.

Triplets with Sum between given range Java Solution

Here an array will be given, we need to find three values whose sum will be in the given range. We can solve this using brute force using three loops but that will give time limit error. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
public class Solution {
    public int solve(ArrayList<String> A) {
        if(A.size() < 3) return 0;

        double a = Double.parseDouble(A.get(0)); 
        double b = Double.parseDouble(A.get(1)); 
        double c = Double.parseDouble(A.get(2)); 

        for(int i = 3; i < A.size(); i++){
            if((a+b+c) > 1 && (a+b+c) < 2){
                return 1;
            }

            double n = Double.parseDouble(A.get(i));
            
           if((a+b+c) >= 2){
                if(a > b && a > c){
                    a = n;
                } else if( b > c){
                    b = n;
                } else{
                    c = n;
                }
            } 
            else{
                if(a < b && a < c){
                    a = n;
                } else if( b < c){
                    b = n;
                } else{
                    c = n;
                }
            }
        }
        
        if((a+b+c) > 1 && (a+b+c) < 2){
            return 1;
        }
       
        return 0;

    }
}



Other Posts You May Like
Please leave a comment below if you like this post or found some error, it will help me to improve my content.
By

Comments

Post a Comment

Popular Posts from this Blog

Java Method Overloading - The Coding Shala

Image
Home >> Learn Java >> Java Method Overloading Java Method Overloading Java class can have more than one method with the same name but different in parameters, known as Method Overloading. Question: What is the use of method overloading? Answer:  Suppose we want to perform some operation like an addition but addition can be performed between two numbers, three numbers or two floats or more. So instead of using different methods, we use the same name of the method with different parameters. This can increase the readability of the program. Method overloading can be achieved by changing numbers of arguments or by changing the data types. Example of Method Overloading in Java The following example explains Method Overloading: //Method Overloading example class Addition { public int add ( int a , int b ){ return a + b ; } public int add ( int a , int b , int c ){ return a + b + c ; ...
Read more

Java Program to Convert Decimal to Binary - The Coding Shala

Home >> Java Programs >> Convert Decimal to Binary  Hey there, welcome back to another post. In this post, we will learn how to convert decimal to binary in Java. Java Program to Convert Decimal to Binary You have given a decimal number. Write a Java program to convert decimal to binary. Example 1:  Input: 7 Output: 111 Input: 10 Output: 1010 Decimal to Binary Conversion using Array Approach To convert decimal to binary we can follow the below steps: Store the remainder in the array when we divide the number by 2. Divide the number by 2. Follow the above two steps until the number is above 0. Print the array in reverse order. For example:  4 % 2 = 0 => 4/2 = 2 2 % 2 = 0 => 2/2 = 1 1 % 2 = 1 => 1/2 = 0 Binary of 4 is: 100 Java Program:  import java.util.ArrayList; import java.util.List; import java.util.Scanner; /** * https://www.thecodingshala.com/ */ public class Main { public static void printBina...
Read more

Java Program to Find GCD or HCF of Two Numbers - The Coding Shala

Home >> Java Programs >> Find GCD of Two Numbers  Hey there, welcome back to another post. In this post, we will learn how to find GCD or HCF of Two Numbers in Java. Java Program to Find GCD or HCF of Two Numbers The GCD (Greatest Common Divisor) or HCF (Highest Common Factor) of two numbers is the largest number that divides both of them. For example:  Number1: 6 (2 * 3) Number2: 9 (3 * 3) GCD or HCF of 6 and 9 is: 3 Find GCD of Two Numbers in Java using for Loop As we already know, GCD is the largest number that divides both numbers. We can start a for loop from 1 (because 1 divides all the numbers) to both numbers and if it divides both numbers then update GCD. Java Program:  import java.util.Scanner; /** * https://www.thecodingshala.com/ */ public class Main { public static void findGCD( int num1, int num2) { int gcd = 1; if (num1 == 0) { gcd = num2; } if (num2 == 0) { ...
Read more

Spiral Order Matrix II - The Coding Shala

Image
Home >> Interview Questions >> Spiral Order matrix 2 Spiral Order Matrix II Problem Solution Given an integer n, generate a square matrix filled with elements from 1 to n 2  in spiral order. Example: Given n = 3, You should return the following matrix: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ] Solution: (Java) The concept is the same as how to print the Spiral Order Matrix. Approach: Let's see for n= 4, then numbers will come from 1 to 16(n*n) in the matrix. As we need to insert numbers in spiral order so here we need 4 things to check, first and last column and top and bottom row. The following four steps we need to do: First, we need to insert numbers in the top row. Our loop will go from the left column to the right then will increase the top row by one and now the top is our second row. Now we are inserting the numbers in the right column, will start the loop from top to bottom, and then decrease the value of the right ...
Read more

LeetCode - Crawler Log Folder Solution - The Coding Shala

Home >> LeetCode >> Crawler Log Folder  In this post, we will learn how to solve LeetCode's Crawler Log Folder problem and will implement Crawler Log Folder Java Solution. Crawler Log Folder Problem The Leetcode file system keeps a log each time some user performs a change folder operation. The operations are described below: "../": Move to the parent folder of the current folder. (If you are already in the main folder, remain in the same folder). "./": Remain in the same folder. "x/": Move to the child folder named x (This folder is guaranteed to always exist). You are given a list of strings logs where logs[i] is the operation performed by the user at the ith step. The file system starts in the main folder, then the operations in logs are performed. Return the minimum number of operations needed to go back to the main folder after the change folder operations. Input: logs = ["d1/","d2/","../","d2...
Read more