### Replace All Digits with Characters LeetCode Solution - The Coding Shala

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In this post, we will learn how to solve LeetCode's Replace All Digits with Characters Problem and will implement its solution in Java.

## Replace All Digits with Characters Problem

You are given a 0-indexed string s that has lowercase English letters in its even indices and digits in its odd indices. There is a function shift(c, x), where c is a character and x is a digit, that returns the xth character after c. For example, shift('a', 5) = 'f' and shift('x', 0) = 'x'. For every odd index i, you want to replace the digit s[i] with shift(s[i-1], s[i]).

Return s after replacing all digits. It is guaranteed that shift(s[i-1], s[i]) will never exceed 'z'.

Example 1:
Input: s = "a1c1e1"
Output: "abcdef"
Explanation: The digits are replaced as follows:
- s[1] -> shift('a',1) = 'b'
- s[3] -> shift('c',1) = 'd'
- s[5] -> shift('e',1) = 'f'

Example 2:
Input: s = "a1b2c3d4e"
Output: "abbdcfdhe"
Explanation: The digits are replaced as follows:
- s[1] -> shift('a',1) = 'b'
- s[3] -> shift('b',2) = 'd'
- s[5] -> shift('c',3) = 'f'
- s[7] -> shift('d',4) = 'h'

Practice this problem on LeetCode.

## LeetCode - Replace All Digits with Characters Java Solution

Approach 1

Straight forward solution.

Java Program:

```class Solution {
public String replaceDigits(String s) {
// convert into char array
char[] arr = s.toCharArray();
for(int i = 1; i < arr.length; i += 2) {
// shift the char using digit
arr[i] = (char)(arr[i-1] + arr[i]-'0');
}
return String.valueOf(arr);
}
}
```

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