Replace All Digits with Characters LeetCode Solution - The Coding Shala

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 In this post, we will learn how to solve LeetCode's Replace All Digits with Characters Problem and will implement its solution in Java.

Replace All Digits with Characters Problem

You are given a 0-indexed string s that has lowercase English letters in its even indices and digits in its odd indices. There is a function shift(c, x), where c is a character and x is a digit, that returns the xth character after c. For example, shift('a', 5) = 'f' and shift('x', 0) = 'x'. For every odd index i, you want to replace the digit s[i] with shift(s[i-1], s[i]).

Return s after replacing all digits. It is guaranteed that shift(s[i-1], s[i]) will never exceed 'z'.

Example 1:
Input: s = "a1c1e1"
Output: "abcdef"
Explanation: The digits are replaced as follows:
- s[1] -> shift('a',1) = 'b'
- s[3] -> shift('c',1) = 'd'
- s[5] -> shift('e',1) = 'f'

Example 2:
Input: s = "a1b2c3d4e"
Output: "abbdcfdhe"
Explanation: The digits are replaced as follows:
- s[1] -> shift('a',1) = 'b'
- s[3] -> shift('b',2) = 'd'
- s[5] -> shift('c',3) = 'f'
- s[7] -> shift('d',4) = 'h'

Practice this problem on LeetCode.

LeetCode - Replace All Digits with Characters Java Solution

Approach 1

Straight forward solution.

Java Program: 

class Solution {
    public String replaceDigits(String s) {
        // convert into char array
        char[] arr = s.toCharArray();
        for(int i = 1; i < arr.length; i += 2) {
            // shift the char using digit
            arr[i] = (char)(arr[i-1] + arr[i]-'0');
        }
        return String.valueOf(arr);
    }
}


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