### Detect Cycle in a Linked List - The Coding Shala

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## Detect Cycle in a Linked List

Given a linked list, determine if it has a cycle in it.

To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where the tail connects to. If pos is -1, then there is no cycle in the linked list.

Example 1:

Input: head = [3,2,0,-4], pos = 1
Output: true
Explanation: There is a cycle in the linked list, where the tail connects to the second node.

Input: head = [1,2], pos = 0
Output: true
Explanation: There is a cycle in the linked list, where the tail connects to the first node.

Input: head = [1], pos = -1
Output: false
Explanation: There is no cycle in the linked list.

### Detect Cycle in a Linked List Java Program

Approach:
We can do it using HashSet. we check in the linked list if the current element is visited or not, if not then we add it to the set else return true but this would take additional O(n) Space.

The alternative we can use two pointers. One slow pointer and one fast. The slow pointer will move by 1 step, fast by 2 steps. If there is a cycle available in the linked list then the fast pointer will catch up the slow pointer otherwise it will reach the null(end).

Java Code

```/**
* class ListNode {
*     int val;
*     ListNode next;
*     ListNode(int x) {
*         val = x;
*         next = null;
*     }
* }
*/
public class Solution {
while(fast != null){
if(slow == fast) return true;
if(fast.next == null) return false;
slow = slow.next;
fast = fast.next.next;
}
return false;
}
}
```

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